2x^2-446x+19964=0

Solution for 2x^2-446x+19964=0 equation:

2x^2-446x+19964=0

a = 2; b = -446; c = +19964;
Δ = b2-4ac
Δ = -4462-4·2·19964
Δ = 39204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{39204}=198$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-446)-198}{2*2}=\frac{248}{4}
=62
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-446)+198}{2*2}=\frac{644}{4}
=161
$